Solveeit Logo

Question

Question: A 0-25 mA ammeter having resistance 10 $\Omega$ is to be converted into voltmeter with a range 0-25 ...

A 0-25 mA ammeter having resistance 10 Ω\Omega is to be converted into voltmeter with a range 0-25 V. The resistance connected in series is

A

900 Ω\Omega

B

990 Ω\Omega

C

1000 Ω\Omega

D

1100 Ω\Omega

Answer

990 Ω\Omega

Explanation

Solution

Here's how to calculate the series resistance:

  1. Full-scale current:

    I=25 mA=0.025 AI = 25 \text{ mA} = 0.025 \text{ A}

  2. Voltage drop across the ammeter:

    Va=I×10Ω=0.025×10=0.25VV_a = I \times 10\,\Omega = 0.025 \times 10 = 0.25\,\text{V}

  3. Extra voltage to be developed by the series resistor:

    Vs=25V0.25V=24.75VV_s = 25\,\text{V} - 0.25\,\text{V} = 24.75\,\text{V}

  4. Calculate series resistance:

    Rs=VsI=24.750.025=990ΩR_s = \dfrac{V_s}{I} = \dfrac{24.75}{0.025} = 990\,\Omega