Question

600 mL of 0.01M HCl is mixed with 400 mL of 0.01 M H2SO4 .The pH of the mixture is ______ × 10-2 (Nearest integer)
[Given log 2 =0.30 , log 3 =0.48 log 5 =0.69 log 7 -0.84 log 11 =1.04 ]

Answer 1

The correct answer is 186.
Total milimoles of H+=(600×0.01)+(400×0.01×2)
=14
[H+]=100014​=14×10−3
pH=3−log14
=1.86
=186×10−2