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Question

Chemistry Question on Thermodynamics

6 moles of an ideal gas expand isothermally and reversibly from a volume of 1 litre to a volume of 10 litres at 27?C. What is the maximum work done?

A

47 kJ

B

100 kJ

C

0

D

34.465 kJ

Answer

34.465 kJ

Explanation

Solution

W = - 2.303 nRT log V2V1\frac{V_2}{V_1}
Given n = 6, T = 27?C = 273 + 27 = 300 K
V1 = 1 L, V2 = 10 L
\therefore W = - 2.303 ? 6 ? 8.314 ? 300 log 101\frac{10}{1}
=34.465 kJ