Solveeit Logo

Question

Question: The set of quantum numbers, n = 3, l = 2, $m_l$ = 0...

The set of quantum numbers, n = 3, l = 2, mlm_l = 0

A

describes an electron in a 2s orbital

B

is not allowed

C

describes an electron in a 3p orbital

D

describes one of the five orbitals of same energy

Answer

describes one of the five orbitals of same energy

Explanation

Solution

The principal quantum number is n=3n=3. The azimuthal quantum number is l=2l=2. This is allowed as ln1l \le n-1 (2312 \le 3-1). l=2l=2 corresponds to a d-subshell. For l=2l=2, the magnetic quantum number mlm_l can take values from l-l to +l+l. The given ml=0m_l=0 is a valid value since 202-2 \le 0 \le 2. The set (n=3,l=2n=3, l=2) defines the 3d subshell. For l=2l=2, the number of orbitals is 2l+1=2(2)+1=52l+1 = 2(2)+1=5. These 5 orbitals (with ml=2,1,0,+1,+2m_l = -2, -1, 0, +1, +2) are degenerate, meaning they have the same energy. The given quantum numbers specify one of these five 3d orbitals.