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Question

Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

59 g of an amide obtained from a carboxylic acid, RCOOH, upon heating with alkali liberated 17 g of ammonia. The acid is

A

Formic acid

B

Acetic acid

C

Propionic acid

D

Benzoic acid.

Answer

Acetic acid

Explanation

Solution

RCONH2+NaOHRCOONa+NH3RCONH_2 + NaOH \rightarrow RCOONa + NH_3 As 1 mole of NH3 is given by one mole of amide. Thus mol. mass of RCONH2RCONH_2 is A + 12 + 16 + 14 + 2 = 59 or A + 44 = 59 A = 59 - 44 = 15 Hence alkyl group with mol. mass A = 15 is CH3CH_3 Thus, acid is CH3COOHCH_3COOH .