Question
Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques
59 g of an amide obtained from a carboxylic acid, RCOOH, upon heating with alkali liberated 17 g of ammonia. The acid is
A
Formic acid
B
Acetic acid
C
Propionic acid
D
Benzoic acid.
Answer
Acetic acid
Explanation
Solution
RCONH2+NaOH→RCOONa+NH3 As 1 mole of NH3 is given by one mole of amide. Thus mol. mass of RCONH2 is A + 12 + 16 + 14 + 2 = 59 or A + 44 = 59 A = 59 - 44 = 15 Hence alkyl group with mol. mass A = 15 is CH3 Thus, acid is CH3COOH .