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Question: A liquid when kept inside a thermally insulated closed vessel at 25°C was mechanically stirred from ...

A liquid when kept inside a thermally insulated closed vessel at 25°C was mechanically stirred from outside. What will be the correct option for the following thermodynamic parameters ?

A

ΔU>0,q=0,w>0\Delta U > 0, q = 0, w > 0

B

ΔU=0,q=0,w=0\Delta U = 0, q = 0, w = 0

C

ΔU<0,q=0,w>0\Delta U < 0, q = 0, w > 0

D

ΔU=0,q<0,w>0\Delta U = 0, q<0, w > 0

Answer

(1) ΔU>0,q=0,w>0\Delta U > 0,\, q = 0,\, w > 0

Explanation

Solution

Since the container is thermally insulated, no heat is exchanged, so

q=0.q = 0.

Mechanical stirring does work on the liquid, increasing its internal energy, hence

w>0andΔU>0.w > 0 \quad \text{and} \quad \Delta U > 0.