Question
Question: Consider the system of equations a₁x + b₁y + c₁z = 0, a₂x + b₂y + c₂z = 0, a₃x + b₃y + c₃z = 0 if \...
Consider the system of equations a₁x + b₁y + c₁z = 0, a₂x + b₂y + c₂z = 0, a₃x + b₃y + c₃z = 0 if
a1a2a3b1b2b3c1c2c3=0,then the system has

A
more than two solutions
B
only non trivial solutions
C
no solution
D
only trivial solution (0, 0,0)
Answer
more than two solutions
Explanation
Solution
Key Observation: This is a homogeneous system Ax=0.
Determinant Zero: Δ=det(A)=0.
- For a homogeneous system, if Δ=0 then there are infinitely many (i.e.\ more than two) solutions.
- We have Δx=Δy=Δz=0 automatically, confirming non-uniqueness.
Conclusion: The system has more than two solutions.