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Question: Consider the system of equations a₁x + b₁y + c₁z = 0, a₂x + b₂y + c₂z = 0, a₃x + b₃y + c₃z = 0 if \...

Consider the system of equations a₁x + b₁y + c₁z = 0, a₂x + b₂y + c₂z = 0, a₃x + b₃y + c₃z = 0 if

a1b1c1a2b2c2a3b3c3=0,\begin{vmatrix} a_1 & b_1 & c_1\\ a_2 & b_2 & c_2\\ a_3 & b_3 & c_3 \end{vmatrix} = 0,

then the system has

A

more than two solutions

B

only non trivial solutions

C

no solution

D

only trivial solution (0, 0,0)

Answer

more than two solutions

Explanation

Solution

Key Observation: This is a homogeneous system Ax=0\mathbf{A}\mathbf{x} = \mathbf{0}.
Determinant Zero: Δ=det(A)=0\Delta = \det(\mathbf{A}) = 0.

  • For a homogeneous system, if Δ=0\Delta = 0 then there are infinitely many (i.e.\ more than two) solutions.
  • We have Δx=Δy=Δz=0\Delta_x=\Delta_y=\Delta_z=0 automatically, confirming non-uniqueness.
    Conclusion: The system has more than two solutions.