Question
Question: Total number of space (stereo) isomers of complex ion $[Cr(gly)(en)_2]^{2+}$ are ____....
Total number of space (stereo) isomers of complex ion [Cr(gly)(en)2]2+ are ____.

3
Solution
The complex ion is [Cr(gly)(en)2]2+. Here, Cr is the central metal ion. gly (glycinate ion, NH2−CH2−COO−) is an unsymmetrical bidentate ligand, coordinating through one Nitrogen (N) atom and one Oxygen (O) atom. We can denote it as AB. en (ethylenediamine, NH2−CH2−CH2−NH2) is a symmetrical bidentate ligand, coordinating through two Nitrogen (N) atoms. We can denote it as AA.
The coordination number of Cr is 2×2(from two en)+2×1(from one gly)=6. So, it is an octahedral complex. The complex is of the type [M(AA)2(AB)].
For an octahedral complex of the type [M(AA)2(AB)], there are two possible geometrical isomers:
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trans-isomer: In this isomer, the two symmetrical bidentate ligands (
en) are arranged in a 'trans' fashion relative to each other. This means their 'planes' are parallel and they are on opposite sides of the central metal ion.- Let's visualize this. Imagine the two
enligands occupying positions such that they are opposite to each other. For example, if oneenoccupies the top-front and top-back positions, the otherenwould occupy the bottom-front and bottom-back positions. - The
glyligand (N, O) would then occupy the remaining two adjacent positions. - This
transisomer possesses a plane of symmetry (passing through the Cr atom and bisecting the twoenligands, and containing theglyligand). Therefore, thetransisomer is optically inactive (it is a meso compound). - Number of stereoisomers for the
transform = 1.
- Let's visualize this. Imagine the two
-
cis-isomer: In this isomer, the two symmetrical bidentate ligands (
en) are arranged in a 'cis' fashion relative to each other. This means their 'planes' are not parallel, and they are on the same side of the central metal ion, or at least not directly opposite.- This
cisisomer lacks a plane of symmetry and is chiral. Therefore, it exists as a pair of enantiomers (non-superimposable mirror images). - Number of stereoisomers for the
cisform = 2 (dextro and levo forms).
- This
Total number of space (stereo) isomers = (Number of trans-isomers) + (Number of cis-enantiomers)
Total number of space (stereo) isomers = 1 (trans) + 2 (cis-enantiomers) = 3.
Therefore, there are 3 possible space (stereo) isomers for the complex ion [Cr(gly)(en)2]2+.
