Question
Question: Total number of space (stereo) isomers of complex ion $[Cr(gly)(en)_2]^{2+}$ are ____....
Total number of space (stereo) isomers of complex ion [Cr(gly)(en)2]2+ are ____.

3
Solution
The complex ion is [Cr(gly)(en)2]2+. Here, Cr
is the central metal ion. gly
(glycinate ion, NH2−CH2−COO−) is an unsymmetrical bidentate ligand, coordinating through one Nitrogen (N) atom and one Oxygen (O) atom. We can denote it as AB
. en
(ethylenediamine, NH2−CH2−CH2−NH2) is a symmetrical bidentate ligand, coordinating through two Nitrogen (N) atoms. We can denote it as AA
.
The coordination number of Cr is 2×2(from two en)+2×1(from one gly)=6. So, it is an octahedral complex. The complex is of the type [M(AA)2(AB)].
For an octahedral complex of the type [M(AA)2(AB)], there are two possible geometrical isomers:
-
trans-isomer: In this isomer, the two symmetrical bidentate ligands (
en
) are arranged in a 'trans' fashion relative to each other. This means their 'planes' are parallel and they are on opposite sides of the central metal ion.- Let's visualize this. Imagine the two
en
ligands occupying positions such that they are opposite to each other. For example, if oneen
occupies the top-front and top-back positions, the otheren
would occupy the bottom-front and bottom-back positions. - The
gly
ligand (N, O) would then occupy the remaining two adjacent positions. - This
trans
isomer possesses a plane of symmetry (passing through the Cr atom and bisecting the twoen
ligands, and containing thegly
ligand). Therefore, thetrans
isomer is optically inactive (it is a meso compound). - Number of stereoisomers for the
trans
form = 1.
- Let's visualize this. Imagine the two
-
cis-isomer: In this isomer, the two symmetrical bidentate ligands (
en
) are arranged in a 'cis' fashion relative to each other. This means their 'planes' are not parallel, and they are on the same side of the central metal ion, or at least not directly opposite.- This
cis
isomer lacks a plane of symmetry and is chiral. Therefore, it exists as a pair of enantiomers (non-superimposable mirror images). - Number of stereoisomers for the
cis
form = 2 (dextro and levo forms).
- This
Total number of space (stereo) isomers = (Number of trans-isomers) + (Number of cis-enantiomers)
Total number of space (stereo) isomers = 1 (trans) + 2 (cis-enantiomers) = 3.
Therefore, there are 3 possible space (stereo) isomers for the complex ion [Cr(gly)(en)2]2+.