Question

500 mL of nitrogen at $27^\circ C$ is cooled to $-5^\circ C$ at the same pressure. The new volume becomes

• A. 326.32 mL
• B. 446.66 mL
• C. 546.32 mL
• D. 771.56mL

Answer 1

Answer: (B)

446.66 mL

Answer 2

Initial volume, $V_1 = 500 mL$
Initial temperature,
$T_1 = 27^\circ C = 27 + 273 = 300 K$
Final temperature,
$T_2 = - 5 + 273 = 268 K$
$V_2=?$
$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$V_2=\frac{V_1 T_2}{T_1}$

$V_2=\frac{500\times268}{300}$
$V_2=446.66\ mL$

So, the correct option is (B): 446.66 mL