Question

50.0 mL of 0.10 M HCl is mixed with 50.0 mL of 0.10 M NaOH. The solution's temperature rises by 3.0ŗC. Calculate the enthalpy of neutralization per mole of HCl.

• A. –2.5×102 kJ/mole
• B. –1.3×102 kJ/mole
• C. –8.4×101 kJ/mole
• D. –6.3×101 kJ/mole

Answer 1

Answer: (A)

–2.5×102 kJ/mole

Answer 2

Assuming density of solution is 1g/cc

and specipic heat is 4.2 J/gc

q = ms$\Delta$T = 100 × 4.2 × 3

millimoles of acid nuetralized = 5

$\Delta$H = – 100 × 4.2 × 3 ×$\frac{1000}{5}$ = – 2.52 × 102 kJ/mole.