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Question: \(50 \Omega\) and \(100 \Omega\) resistors are connected in series. This connection is connected wi...

50Ω50 \Omega and 100Ω100 \Omega resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100Ω100 \Omega resistance is connected across 100Ω100 \Omega resistor, then the reading of the voltmeter will be

A

1.6 V

B

1.0 V

C

1.2 V

D

2.0 V

Answer

1.2 V

Explanation

Solution

Equivalent resistance of the circuit Req=100ΩR _ { e q } = 100 \Omega current through the circuit

P.D. across combination of voltmeter and 100 Ω resistances =2.4100×50=1.2 V= \frac { 2.4 } { 100 } \times 50 = 1.2 \mathrm {~V}

Since the voltmeter and 100 Ω resistance are in parallel, so the voltmeter reads the same value i.e. 1.2V.