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Question

Chemistry Question on Acids and Bases

50mL50 \, mL of H2OH_2O is added to 50mL50 \, mL of 1×103M1 \times 10^{-3}\, M barium hydroxide solution. What is the pH of the resulting solution?

A

3

B

3.3

C

11

D

11.7

Answer

11

Explanation

Solution

In water, barium hydroxide is hydrolysed as follows,
Ba(OH)2Ba2++2OHBa ( OH )_{2} \rightleftharpoons Ba ^{2+}+2 OH ^{-}
cone, of Ba2+=1×103MBa ^{2+}=1 \times 10^{-3} M
cone. Of [OH]=2×1×103M\left[ OH ^{-}\right]=2 \times 1 \times 10^{-3} M
=2×103M=2 \times 10^{-3} M
pOH=log[OH]pOH =-\log [ OH^ -]
=log(2×103)=-\log \left(2 \times 10^{-3}\right)
=2.69=2.69
pH+pOH=14p H+p O H=14
pH=14pOHp H=14-p O H
=142.69=14-2.69
=11.3=11.3
=11.0=11.0