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Question

Chemistry Question on Some basic concepts of chemistry

50mL50 \,mL of an aqueous solution of glucose contains 6.02×10226.02 \times 10^{22} molecules. The concentration of solution is

A

0.1M0.1\,M

B

1.0M1.0 \,M

C

0.2M0.2\, M

D

2.0M2.0 \,M

Answer

2.0M2.0 \,M

Explanation

Solution

Mole of glucose =6.02×10226.02×1023=0.1 = \frac{6.02\,\times\,10^{22}}{6.02\,\times\,10^{23} } = 0.1 Mglucose=0.1×100050=2\therefore M_{glucose} = \frac{0.1\,\times\,1000}{50} = 2