Question
Question: 50 gm of ice at 0<sup>0</sup>C is mixed with 50 gm of water at 80<sup>0</sup>C. The final temperatur...
50 gm of ice at 00C is mixed with 50 gm of water at 800C. The final temperature of mixture is: (latent heat of fusion of ice = 80 cal/g, sw = 1 cal/g0C)
A
00
B
400C
C
600C
D
Less than 00C
Answer
00
Explanation
Solution
Heat required by the ice 50 × 80 = 4000 cal
heat released by water
50 × 1 × 80 = 400 cal
both are equal. Final temperature = 00C