Question

50 gm of ice at 0°C is mixed with 50 gm of water at 80°C, final temperature of mixture will be

• A. 0°C
• B. 40°C
• C. 30°C
• D. 4°C

Answer 1

Answer: (A)

0°C

Answer 2

$\theta_{\text{mix}} = \frac{\theta_{W} - \frac{L_{i}}{c_{W}}}{2} = \frac{80 - \frac{80}{1}}{2} = 0$