Question

50 gm ice at 0°C in insulator vessel, 50g water of 100°C is mixed in it, then final temperature of the mixture is (neglect the heat loss)

• A. 10°C
• B. $0{^\circ} < < T_{m} < 20{^\circ}C$
• C. 20°C
• D. Above 20°C

Answer 1

Answer: (A)

10°C

Answer 2

$\theta_{\text{mix}} = \frac{\theta_{W} - \frac{L_{i}}{C_{W}}}{2} = \frac{100 - \frac{80}{1}}{2} = 10{^\circ}C$