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Question: Two different composite numbers A and B are factorised as: $A = (5^p \times 2^q)$ and $B = (3^p \ti...

Two different composite numbers A and B are factorised as:

A=(5p×2q)A = (5^p \times 2^q) and B=(3p×2q)B = (3^p \times 2^q), where pp and qq are WHOLE numbers.

If LCMLCM of AA and BB always ends with 5 which of the following is the HCFHCF of AA and BB?

A

2

B

5

C

15

D

1

Answer

1

Explanation

Solution

To ensure that the LCM of A and B ends with 5 (i.e., is odd), there must be no factor of 2. This forces q = 0. Hence,

A=5pA = 5^p and B=3pB = 3^p.

Since 5 and 3 are distinct primes, their only common factor is 1. Thus,

HCF = 1.