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Question: Q is a variable point whose locus is 2x + 3y + 4 = 0; corresponding to a particular position of Q, P...

Q is a variable point whose locus is 2x + 3y + 4 = 0; corresponding to a particular position of Q, P is the point of section of OQ, O being the origin, such that OP : PQ = 3 : 1. Find the locus of P?

A

2x + 3y + 3 = 0

B

2x - 3y + 3 = 0

C

3x + 2y + 3 = 0

D

3x - 2y + 3 = 0

Answer

2x + 3y + 3 = 0

Explanation

Solution

Let P be (h,k)(h, k) and Q be (xQ,yQ)(x_Q, y_Q). O is the origin (0,0)(0,0). Since P divides OQ in the ratio OP : PQ = 3 : 1, we use the section formula: h=1xO+3xQ1+3=0+3xQ4    xQ=4h3h = \frac{1 \cdot x_O + 3 \cdot x_Q}{1+3} = \frac{0 + 3x_Q}{4} \implies x_Q = \frac{4h}{3} k=1yO+3yQ1+3=0+3yQ4    yQ=4k3k = \frac{1 \cdot y_O + 3 \cdot y_Q}{1+3} = \frac{0 + 3y_Q}{4} \implies y_Q = \frac{4k}{3} Q lies on the line 2x+3y+4=02x + 3y + 4 = 0. Substitute the expressions for xQx_Q and yQy_Q: 2(4h3)+3(4k3)+4=02\left(\frac{4h}{3}\right) + 3\left(\frac{4k}{3}\right) + 4 = 0 Simplify the equation: 8h3+4k+4=0\frac{8h}{3} + 4k + 4 = 0 Multiply by 3: 8h+12k+12=08h + 12k + 12 = 0 Divide by 4: 2h+3k+3=02h + 3k + 3 = 0 The locus of P is 2x+3y+3=02x + 3y + 3 = 0.