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Question: Two bodies of masses 2 Kg and 7 Kg are moving with velocities of 2 m/s and 7 m/s respectively. What ...

Two bodies of masses 2 Kg and 7 Kg are moving with velocities of 2 m/s and 7 m/s respectively. What is the total momentum of the system in Kg-m/s?

A

50

B

25

C

53

D

0

Answer

53 Kg-m/s

Explanation

Solution

The momentum of an object is the product of its mass and velocity. For a system of multiple objects, the total momentum is the vector sum of the individual momenta. Since no directions are specified, we assume the bodies are moving in the same direction, so their momenta add up arithmetically.

  1. Calculate the momentum of the first body (p1=m1v1p_1 = m_1 v_1).
  2. Calculate the momentum of the second body (p2=m2v2p_2 = m_2 v_2).
  3. Add the individual momenta to find the total momentum (Ptotal=p1+p2P_{total} = p_1 + p_2).
  • Body 1:

    p1=m1×v1=2 Kg×2 m/s=4 Kg-m/sp_1 = m_1 \times v_1 = 2 \text{ Kg} \times 2 \text{ m/s} = 4 \text{ Kg-m/s}

  • Body 2:

    p2=m2×v2=7 Kg×7 m/s=49 Kg-m/sp_2 = m_2 \times v_2 = 7 \text{ Kg} \times 7 \text{ m/s} = 49 \text{ Kg-m/s}

  • Total Momentum:

    Ptotal=p1+p2=4 Kg-m/s+49 Kg-m/s=53 Kg-m/sP_{total} = p_1 + p_2 = 4 \text{ Kg-m/s} + 49 \text{ Kg-m/s} = 53 \text{ Kg-m/s}