Question
Chemistry Question on Thermodynamics
5 moles of an ideal gas at 100K are allowed to undergo reversible compression till its temperature becomes 200K. If CV=28JK−1mol−1,caculateΔU and ΔpV for this process. (R=8.0JK−1mol−1]
A
ΔU=14kJ:Δ(pV)=4kJ
B
ΔU=14kJ:Δ(pV)=18kJ
C
ΔU=2.8kJ:Δ(pV)=0.8kJ
D
ΔU=14kJ:Δ(pV)=0.8kJ
Answer
ΔU=14kJ:Δ(pV)=4kJ
Explanation
Solution
ΔU=nCVm×ΔT =5×28×100=14kJ ΔPV=nRΔT =5×8×100=4kJ