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Question: Let C: y² = 4ax, a>0 be a parabola with Focus F. Through point P on parabola in first Quadrant and Q...

Let C: y² = 4ax, a>0 be a parabola with Focus F. Through point P on parabola in first Quadrant and Q on negative x-axis the tangent PQ is drawn to C with |PQ|=2. Circles C₁ and C₂ are tangent to line OP at P and are both tanget to x-axis. The coordinate of F for which sum of areas of C₁ and C₂ is minimum is. (1nn,0)\left(\frac{1}{\sqrt{n}-\sqrt{n}}, 0\right). Then n is ___

Answer

The provided problem statement contains a typo in the coordinate of F. The expression (1nn,0)\left(\frac{1}{\sqrt{n}-\sqrt{n}}, 0\right) simplifies to (10,0)\left(\frac{1}{0}, 0\right), which is undefined. Assuming there is a typo and the intended coordinate of F is of the form (a,0)(a,0) where aa is related to nn, and that the sum of areas is minimized for a specific value of aa. The sum of areas A=4π3+1+4/a21+1+4/a2A = 4\pi \frac{3+\sqrt{1+4/a^2}}{1+\sqrt{1+4/a^2}}. This area is minimized when aa is minimized. If we assume the question implies a specific value of aa is obtained, and if the coordinate of F was intended to be (1k,0)\left(\frac{1}{k}, 0\right) for some kk, then a=1ka = \frac{1}{k}. The area is minimized as a0+a \to 0^+. If the question intended a=12na = \frac{1}{2\sqrt{n}}, and the minimum area occurs at this aa, then we need more information or a corrected problem statement to determine nn. Given the ambiguity, a definitive answer for nn cannot be provided.

Explanation

Solution

The problem statement has a significant typo in the coordinate of the Focus F: (1nn,0)\left(\frac{1}{\sqrt{n}-\sqrt{n}}, 0\right). This simplifies to (10,0)\left(\frac{1}{0}, 0\right), which is an undefined coordinate. This makes it impossible to proceed with finding a specific value for nn.

Assuming the question meant that the coordinate of F is (a,0)(a,0) and the sum of areas is minimized for a particular value of aa which is related to nn. The sum of the areas of the two circles is given by A=4π3+1+4/a21+1+4/a2A = 4\pi \frac{3+\sqrt{1+4/a^2}}{1+\sqrt{1+4/a^2}}. Let Y=1+4/a2Y = \sqrt{1+4/a^2}. Then A=4π3+Y1+Y=4π(1+21+Y)A = 4\pi \frac{3+Y}{1+Y} = 4\pi \left(1 + \frac{2}{1+Y}\right). To minimize AA, we need to maximize 1+Y1+Y, which means maximizing Y=1+4/a2Y = \sqrt{1+4/a^2}. Maximizing YY implies maximizing 1+4/a21+4/a^2, which means maximizing 4/a24/a^2, and thus minimizing a2a^2. Since a>0a>0, the sum of areas is minimized as a0+a \to 0^+.

If we assume the intended form of F was (1k,0)\left(\frac{1}{k}, 0\right) and this is the coordinate where the minimum occurs, then a=1ka = \frac{1}{k}. The minimum area occurs as a0a \to 0, implying kk \to \infty.

If we were to assume a typo like a=12na = \frac{1}{2\sqrt{n}} is the value of aa for which the minimum occurs, then a0a \to 0 implies nn \to \infty. This is unlikely for a typical problem.

Without a corrected statement for the coordinate of F, it is impossible to determine the value of nn. The question, as stated, is unsolvable.