Question
Question: Let C: y² = 4ax, a>0 be a parabola with Focus F. Through point P on parabola in first Quadrant and Q...
Let C: y² = 4ax, a>0 be a parabola with Focus F. Through point P on parabola in first Quadrant and Q on negative x-axis the tangent PQ is drawn to C with |PQ|=2. Circles C₁ and C₂ are tangent to line OP at P and are both tanget to x-axis. The coordinate of F for which sum of areas of C₁ and C₂ is minimum is. (n−n1,0). Then n is ___

The provided problem statement contains a typo in the coordinate of F. The expression (n−n1,0) simplifies to (01,0), which is undefined. Assuming there is a typo and the intended coordinate of F is of the form (a,0) where a is related to n, and that the sum of areas is minimized for a specific value of a. The sum of areas A=4π1+1+4/a23+1+4/a2. This area is minimized when a is minimized. If we assume the question implies a specific value of a is obtained, and if the coordinate of F was intended to be (k1,0) for some k, then a=k1. The area is minimized as a→0+. If the question intended a=2n1, and the minimum area occurs at this a, then we need more information or a corrected problem statement to determine n. Given the ambiguity, a definitive answer for n cannot be provided.
Solution
The problem statement has a significant typo in the coordinate of the Focus F: (n−n1,0). This simplifies to (01,0), which is an undefined coordinate. This makes it impossible to proceed with finding a specific value for n.
Assuming the question meant that the coordinate of F is (a,0) and the sum of areas is minimized for a particular value of a which is related to n. The sum of the areas of the two circles is given by A=4π1+1+4/a23+1+4/a2. Let Y=1+4/a2. Then A=4π1+Y3+Y=4π(1+1+Y2). To minimize A, we need to maximize 1+Y, which means maximizing Y=1+4/a2. Maximizing Y implies maximizing 1+4/a2, which means maximizing 4/a2, and thus minimizing a2. Since a>0, the sum of areas is minimized as a→0+.
If we assume the intended form of F was (k1,0) and this is the coordinate where the minimum occurs, then a=k1. The minimum area occurs as a→0, implying k→∞.
If we were to assume a typo like a=2n1 is the value of a for which the minimum occurs, then a→0 implies n→∞. This is unlikely for a typical problem.
Without a corrected statement for the coordinate of F, it is impossible to determine the value of n. The question, as stated, is unsolvable.
