Question

5 g of ice at 0°C is dropped in a beaker containing 20 g of water at 40°C. The final temperature will be

• A. 32°C
• B. 16°C
• C. 8°C
• D. 24°C

Answer 1

Answer: (B)

16°C

Answer 2

For water and ice mixing

$= \frac{20 \times 40 - \frac{5 \times 80}{1}}{5 + 20} = 16{^\circ}C$