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Question: A rod of length l is translating with velocity v making an angle $\theta$ with the length. Find pote...

A rod of length l is translating with velocity v making an angle θ\theta with the length. Find potential difference across the rod.

A

Bvl sinθ\theta

B

Bvl cosθ\theta

C

Bvl2\frac{Bvl}{2}sinθ\theta

D

zero

Answer

Bvl sinθ\theta

Explanation

Solution

The potential difference across the rod is given by the motional EMF, E=(v×B)l\mathcal{E} = (\vec{v} \times \vec{B}) \cdot \vec{l}.

Given that the magnetic field B\vec{B} is perpendicular to the plane containing the velocity v\vec{v} and the length of the rod l\vec{l}, it means B\vec{B} is perpendicular to both v\vec{v} and l\vec{l}.

The component of velocity perpendicular to the rod is vsinθv \sin\theta. This component is also perpendicular to the magnetic field B\vec{B}.

Therefore, the induced EMF is given by the product of the magnetic field strength, the length of the rod, and the component of velocity perpendicular to the rod and magnetic field:

E=Bl(vsinθ)=Bvlsinθ\mathcal{E} = B \cdot l \cdot (v \sin\theta) = Bvl \sin\theta.