Question

5.6 L of a gas at S.T.P. weighs equal to 8 g. The vapour density of gas is

• A. 32
• B. 16
• C. 8
• D. 40

Answer 1

Answer: (B)

16

Answer 2

Mass of $22\cdot4\, L$ gas at $S.T.P$ $=\frac{8\times22\cdot4}{5\cdot6}=32\,g$ Mol. mass $=32$ $\therefore V.D. =\frac32 \times \frac{1}{2}$ $=16$