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Question: A body having its centre of mass at the origin has three of its particles $(a, 0, 0), (0, a, 0), (0,...

A body having its centre of mass at the origin has three of its particles (a,0,0),(0,a,0),(0,0,a)(a, 0, 0), (0, a, 0), (0, 0, a). The moments of inertia of the body about the X and Y axes are 0.20 kg-m² each. The moment of inertia about the Z-axis :

A

Is 0.20 kg-m²

B

Is 0.40 kg-m²

C

Is 0.202\sqrt{2} kg-m²

D

Cannot be deduced with this information

Answer

Is 0.20 kg-m²

Explanation

Solution

The given particle positions (a,0,0)(a, 0, 0), (0,a,0)(0, a, 0), and (0,0,a)(0, 0, a) exhibit symmetry with respect to cyclic permutation of the axes. Coupled with the fact that the moments of inertia about the X and Y axes are equal (Ix=Iy=0.20kg-m2I_x = I_y = 0.20 \, \text{kg-m}^2), this strongly suggests that the body possesses symmetry such that the moment of inertia about the Z-axis is also equal to these values. This symmetry is characteristic of bodies with cubic symmetry about the origin when the axes are principal axes. Therefore, Iz=Ix=IyI_z = I_x = I_y.