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Question

Question: \(4\sec^{4}x + c\)...

4sec4x+c4\sec^{4}x + c

A

sec3x3+c\frac{\sec^{3}x}{3} + c

B

3sec3x+c3\sec^{3}x + c

C

excosec2(2ex+5)6mudx=\int_{}^{}{e^{- x}\text{cose}\text{c}^{2}(2e^{- x} + 5)}\mspace{6mu} dx =

D

None of these

Answer

sec3x3+c\frac{\sec^{3}x}{3} + c

Explanation

Solution

e2x1e2x+1+c\frac{e^{2x} - 1}{e^{2x} + 1} + c

log(e2x+1)x+c\log(e^{2x} + 1) - x + c

log(e2x+1)+c\log(e^{2x} + 1) + c

cosecxlogtanx26mudx=\int_{}^{}{\frac{\text{cosec}x}{{logtan}\frac{x}{2}}\mspace{6mu} dx =}