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Question

Chemistry Question on Solutions

45g45\, g of ethylene glycol (C2H6O2)\left(C_{2} H_{6} O_{2}\right) is mixed with 600g600\, g of water, what is the depression of freezing point?

A

7.9K7.9\, K

B

2.5K2.5\, K

C

6.6K6.6\, K

D

2.2K2.2\, K

Answer

2.2K2.2\, K

Explanation

Solution

Depression of freezing point is given as
ΔTf=Kf×w×1000m×W\Delta T_{f}=\frac{K_{f} \times w \times 1000}{m \times W} For water Kf=1.86gmol1K_{f}=1.86\, g\,mol ^{-1}
w=45gw=45\, g
W=600gW=600\, g
m(C2H6O2)m\left(C_{2} H_{6} O_{2}\right)
=2×12+6×1+2×16=62=2 \times 12+6 \times 1+2 \times 16=62
ΔTf=1.86×45×100062×600=2.25K\therefore \Delta T_{f-}=\frac{1.86 \times 45 \times 1000}{62 \times 600}=2.25 \,K