B \xrightarrow\[\text{2. CO}\_2\text{/140}^\text{o}\text{C}]... | Chemistry - Preparation of Phenols, Chemical Reactions of Phenols (Kolbe's reaction) | SolveeIt | Solveeit

Today, September 3

Question

B $\xrightarrow[\text{2. CO}_2\text{/140}^\text{o}\text{C}]{\text{1. NaOH}}$ C $\xrightarrow{\text{H}^+\text{/H}_2\text{O}}$ D

In this reaction, the end product D is

Visual representation for Chemistry

A

Salicylaldehyde

B

Salicylic acid

C

Phenyl acetate

D

Aspirin

Answer

Salicylic acid

Explanation

Solution

The reaction sequence starts with benzene, which is sulfonated to benzenesulfonic acid (A). Benzenesulfonic acid is then converted to phenol (B) by fusion with NaOH followed by acidification. Phenol (B) undergoes the Kolbe-Schmidt reaction with NaOH and CO₂ at 140°C to form sodium salicylate (C). Finally, acidification of sodium salicylate (C) yields salicylic acid (D).