Question

427

Answer 1

The equivalent resistance of the circuit is $\frac{172}{61} \Omega$.

Answer 2

The circuit contains a 12Ω resistor in parallel with a complex network. The complex network is an unbalanced Wheatstone bridge. The unbalanced bridge is simplified using a Delta-Star transformation. The Delta formed by the 6Ω, 4Ω, and 6Ω resistors (connected to the top terminal and two internal nodes) is converted into a Star configuration. This transformation converts the bridge into a combination of series and parallel resistors, which can then be easily reduced. Finally, the equivalent resistance of the bridge is combined in parallel with the 12Ω resistor to find the total equivalent resistance of the circuit.