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Question: Prism angle of glass prism is 10°. It's refractive index of red and violet colour is 1.51 and 1.52 r...

Prism angle of glass prism is 10°. It's refractive index of red and violet colour is 1.51 and 1.52 respectively. Then its dispersive power will be .

A

0.015

B

0.020

C

0.011

D

0.019

Answer

0.019

Explanation

Solution

The dispersive power (ω\omega) of a prism material is defined as the ratio of its angular dispersion to the mean deviation.

The formula for dispersive power is given by: ω=μvμrμy1\omega = \frac{\mu_v - \mu_r}{\mu_y - 1} where: μv\mu_v is the refractive index for violet light. μr\mu_r is the refractive index for red light. μy\mu_y is the refractive index for yellow (mean) light.

Given values: Refractive index for red colour, μr=1.51\mu_r = 1.51 Refractive index for violet colour, μv=1.52\mu_v = 1.52 Prism angle, A=10A = 10^\circ (This is not required for calculating dispersive power, as dispersive power is an intrinsic property of the material and is independent of the prism angle for thin prisms).

First, calculate the difference in refractive indices for violet and red light: μvμr=1.521.51=0.01\mu_v - \mu_r = 1.52 - 1.51 = 0.01

Next, calculate the mean refractive index (μy\mu_y). Since the refractive index for yellow light is not given, we approximate it as the average of the refractive indices for red and violet light: μy=μr+μv2=1.51+1.522=3.032=1.515\mu_y = \frac{\mu_r + \mu_v}{2} = \frac{1.51 + 1.52}{2} = \frac{3.03}{2} = 1.515

Now, substitute these values into the formula for dispersive power: ω=0.011.5151\omega = \frac{0.01}{1.515 - 1} ω=0.010.515\omega = \frac{0.01}{0.515}

Calculate the value: ω0.019417\omega \approx 0.019417

Rounding to three decimal places, the dispersive power ω0.019\omega \approx 0.019.