Question

6 gm nitrogen on successive reaction with different compounds gets finally converted into [Cr(NH$_3$)$_x$Br$_2$]. Value of x is [Atomic mass : Cr = 52, Br = 80]

Answer 1

4

Answer 2

The complex is [Cr(NH$_3$)$_x$Br$_2$]. Chromium typically forms coordination compounds with a coordination number of 6. NH$_3$ and Br are monodentate ligands. Thus, the sum of the number of NH$_3$ ligands (x) and Br ligands (2) must equal the coordination number 6. So, x + 2 = 6, which gives x = 4. The 6 gm nitrogen information is irrelevant for determining x.