Question

If the atmospheric pressure is $P_a$, then the pressure $P$ at depth $h$ below the surface of a liquid of density $\rho$ open to the atmosphere is

• A. $P_a - \frac{Pgh}{2}$
• B. $P_a - \rho gh$
• C. $P_a$
• D. $P_a + \rho gh$

Answer 1

Answer: (D)

Option (4)

Answer 2

The pressure at a depth $h$ in a liquid open to the atmosphere is given by the formula:

$$P = P_a + \rho g h$$

Thus, the correct option is (4).

Pressure increases by the hydrostatic pressure $\rho g h$ below atmospheric pressure.