Question

4 moles of an ideal gas is at 0°C. At constant pressure it is heated to double its volume, then its final temperature will be

• A. 0°C
• B. 273°C
• C. 546°C
• D. 136.5°C

Answer 1

Answer: (B)

273°C

Answer 2

$\frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow T_{2} = 2 \times T_{1}$ $= 2 \times (273 + 0) = 546K$

⇒ $T_{2} = 273 \times 2 = 546K \Rightarrow 273{^\circ}C$ ⇒ 273°C