Question

4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction $K_{p} = K_{c}(RT)$ ⇌$K_{p} = K_{c}(RT)^{2}$, 2 moles of C and D are formed. The equilibrium constant for the reaction will be.

• A. $H_{2} + I_{2}$
• B. $2HI$
• C. 1
• D. 4

Answer 1

Answer: (C)

1

Answer 2

$2NO(g) + O_{2}(g)$ ⇌ $K_{2} = \frac{1}{K_{1}}$

Sol. Initial conc. 4, 4 0 0

After T time conc. (4-2) (4-2) 2 2

Equilibrium constant = $K_{2} = K_{1}^{2}$