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Question

Question: $\lim_{x\to\infty} tan^{-1}x$...

limxtan1x\lim_{x\to\infty} tan^{-1}x

Answer

π2\frac{\pi}{2}

Explanation

Solution

The limit limxtan1x\lim_{x\to\infty} \tan^{-1}x represents the value the inverse tangent function approaches as its argument xx tends to infinity. The range of tan1x\tan^{-1}x is (π2,π2)(-\frac{\pi}{2}, \frac{\pi}{2}). As xx increases without bound, tan1x\tan^{-1}x approaches the upper limit of its range, which is π2\frac{\pi}{2}. This is because tany\tan y \to \infty as yπ2y \to \frac{\pi}{2}^-.