Solveeit Logo

Question

Question: 4 L of \(0.02\)M aqueous solution of NaCl wad diluted by adding one litre of water. The molality of ...

4 L of 0.020.02M aqueous solution of NaCl wad diluted by adding one litre of water. The molality of the resultant solution is ________.

A

0.0040.004

B

0.0080.008

C

0.0120.012

D

0.0160.016

Answer

0.0160.016

Explanation

Solution

0.02M×4 L=M2×5 L0.02 \mathrm { M } \times 4 \mathrm {~L} = \mathrm { M } _ { 2 } \times 5 \mathrm {~L}

M2=0.02×45=0.016M\mathrm { M } _ { 2 } = \frac { 0.02 \times 4 } { 5 } = 0.016 \mathrm { M }

Here, molality will be equal to molarity as for NaCl, molecular weights is equal to its equivalent weight.