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Question

Question: f'(n)=Cos(n-\frac{(2n+1)\pi}{6})...

f'(n)=Cos(n-\frac{(2n+1)\pi}{6})

Answer

f(n) = \frac{3}{3-\pi} \sin\left(\frac{3-\pi}{3}n - \frac{\pi}{6}\right) + C

Explanation

Solution

Integrate the given derivative f'(n) with respect to n after simplifying the argument of the cosine function.