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Question

Physics Question on Current electricity

4 cells each of emf2 V and internal resistance of 1O1 O are connected in parallel to a load resistor of 2O2 O . Then the current through the load resistor is

A

2A

B

1.5A

C

1A

D

0.888A

Answer

0.888A

Explanation

Solution

The combined resistance of combination is
R=R+r4=2+14=94R' = R + \frac{r}{4} = 2 + \frac{1}{4} = \frac{9}{4}
V=2voltV = 2volt
V=iR\therefore V = iR
i=VR=2×49=89\Rightarrow i = \frac{V}{R} = \frac{2 \times 4}{9} = \frac{8}{9}
=0.888A= 0.888 A