Question

4. At t = 0 block is at rest a constant force of 6N applied on it. Impulse of net force on block from t = 0 to t = 2 sec is $\alpha$ N-S then '$\alpha$' is.

Answer 1

4.16

Answer 2

1. Calculate frictional force:
     Friction = μ·m·g = 0.2 × 2 kg × 9.8 m/s² = 3.92 N

2. Determine net force:
     Net force = Applied force − Friction = 6 N − 3.92 N = 2.08 N

3. Compute impulse over 2 seconds:
     Impulse = Net force × time = 2.08 N × 2 s ≈ 4.16 N·s