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Question: A ring of radius \(R\) having charge \(Q\) is fixed in a horizontal plane. A point mass \(m\) is at ...

A ring of radius RR having charge QQ is fixed in a horizontal plane. A point mass mm is at stable equilibrium at a distance dd from centre of ring as shown. If the charge on point mass is qq, then

A

d>R2d > \frac{R}{\sqrt{2}}

B

d<R2d < \frac{R}{\sqrt{2}}

C

q>63πϵ0R2mgQq > \frac{6\sqrt{3}\pi\epsilon_0 R^2 mg}{Q}

D

q<63πϵ0R2mgQq < \frac{6\sqrt{3}\pi\epsilon_0 R^2 mg}{Q}

Answer

The correct options are (2) and (3).

Explanation

Solution

  1. For a ring, the axial electric field is E=Qd4πϵ0(d2+R2)3/2E=\frac{Qd}{4\pi\epsilon_0(d^2+R^2)^{3/2}}.

  2. Equilibrium requires qE=mgqE=mg and stability demands d2Udz2>0\frac{d^2U}{dz^2}>0 which results in d<R2d < \frac{R}{\sqrt2}.

  3. The function q=4πϵ0mg(d2+R2)3/2Qdq=\frac{4\pi\epsilon_0mg(d^2+R^2)^{3/2}}{Qd} is minimized at d=R2d=\frac{R}{\sqrt2} giving qmin=63πϵ0R2mgQq_{\min}=\frac{6\sqrt3\pi\epsilon_0R^2mg}{Q}. Thus, qq must exceed this value.