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Question

Chemistry Question on Some basic concepts of chemistry

4.28 g4.28 \,g of NaOHNaOH is dissolved in water and the solution is made to 250 cc250 \,cc. What will be the molarity of the solution?

A

0.615 molL−10.615\, mol L^{-1}

B

0.428 molL−10.428\, mol L^{-1}

C

0.99 molL−10.99\, mol L^{-1}

D

0.301 molL−10.301\, mol L^{-1}

Answer

0.428 molL−10.428\, mol L^{-1}

Explanation

Solution

No. of moles of NaOH=4.2840=0.107NaOH =\frac{4.28}{40} = 0.107 Volume of solution =250cm3= 250 cm ^{3} M=nV(inL)=0.107250×1000=0.428 mol L−1 M = \frac { n}{V(in L)} = \frac{0.107}{250} \times 1000 = 0.428\, mol\, L^{-1}