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Question: \(3\overset{\rightarrow}{OD} + \overset{\rightarrow}{DA} + \overset{\rightarrow}{DB} + \overset{\rig...

3OD→+DA→+DB→+DC→=3\overset{\rightarrow}{OD} + \overset{\rightarrow}{DA} + \overset{\rightarrow}{DB} + \overset{\rightarrow}{DC} =

A

OA→+OB→−OC→\overset{\rightarrow}{OA} + \overset{\rightarrow}{OB} - \overset{\rightarrow}{OC}

B

OA→+OB→−BD→\overset{\rightarrow}{OA} + \overset{\rightarrow}{OB} - \overset{\rightarrow}{BD}

C

OA→+OB→+OC→\overset{\rightarrow}{OA} + \overset{\rightarrow}{OB} + \overset{\rightarrow}{OC}

D

None of these

Answer

OA→+OB→+OC→\overset{\rightarrow}{OA} + \overset{\rightarrow}{OB} + \overset{\rightarrow}{OC}

Explanation

Solution

3OD→+DA→+DB→+DC→3\overset{\rightarrow}{OD} + \overset{\rightarrow}{DA} + \overset{\rightarrow}{DB} + \overset{\rightarrow}{DC}

=OD→+DA→+OD→+DB→+OD→+DC→=OA→+OB→+OC→.= \overset{\rightarrow}{OD} + \overset{\rightarrow}{DA} + \overset{\rightarrow}{OD} + \overset{\rightarrow}{DB} + \overset{\rightarrow}{OD} + \overset{\rightarrow}{DC} = \overset{\rightarrow}{OA} + \overset{\rightarrow}{OB} + \overset{\rightarrow}{OC}.