Question

3A ® 2B, rate of reaction +$\frac{d\lbrack B\rbrack}{dt}$ is equal to -

• A. –$\frac { 3 } { 2 }$ $\frac{d\lbrack A\rbrack}{dt}$
• B. –$\frac { 2 } { 3 }$ $\frac{d\lbrack A\rbrack}{dt}$
• C. –$\frac { 1 } { 3 }$ $\frac{d\lbrack A\rbrack}{dt}$
• D. +$\frac{2d\lbrack A\rbrack}{dt}$

Answer 1

Answer: (B)

–\frac { 2 } { 3 }$$\frac{d\lbrack A\rbrack}{dt}

Answer 2

$–\frac{1}{3}\frac{d\lbrack A\rbrack}{dt}$ = $+ \frac{1}{2}\frac{d\lbrack B\rbrack}{dt}$