Question

3A → 2B,rate of reaction +d[B]/dt is equals to

• A. – $\frac{3}{2}\frac{d[A]}{dt}$
• B. – $\frac{2}{3}\frac{d[A]}{dt}$
• C. $-\frac{1}{3}\frac{d[A]}{dt}$
• D. $2d\frac{d[A]}{dt}$

Answer 1

Answer: (B)

– $\frac{2}{3}\frac{d[A]}{dt}$

Answer 2

The correct option is (B) : $\frac{2}{3}\frac{d[A]}{dt}$

3A→2B For the given reaction we can write rate of reaction: −$\frac{1}{3}$=$\frac{d[A]}{dt}$ ​=−\frac{1}{20}$$\frac{d[B]}{dt} ​⇒+$\frac{d[B]}{dt}$= −$\frac{2}{3}\frac{d[A]}{dt}$