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Question: A current carrying infinite wire is passing through the centre of a ring of radius $R$ and perpendic...

A current carrying infinite wire is passing through the centre of a ring of radius RR and perpendicular to plane of the ring. The magnetic flux passing through the ring will be

A

μ0IR4\frac{\mu_0 IR}{4}

B

μ0IR2\frac{\mu_0 IR}{2}

C

μ0IR\mu_0 IR

D

Zero

Answer

Zero

Explanation

Solution

The wire is along the center and perpendicular to the plane of the ring, so if the ring lies in the xy-plane, the wire is along the z-axis.

The magnetic field B\vec{B} due to a long straight wire is given by

B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}

and is directed tangentially (circles around the wire).

Since the ring's area vector (A\vec{A}) points along the z-axis while the magnetic field is tangential in the xy-plane, the dot product BA=0\vec{B} \cdot \vec{A} = 0 at every point.

Therefore, the net magnetic flux through the ring is zero.