Question

Propane nitrile on reaction with ethyl magnesium iodide in presence of dry ether gives complex. This imine complex on acid C-(-(=N)hydrolysis forms $MgI(4) + H_2O$

• A. 3-Pentanone
• B. Propanone
• C. Butanone
• D. 2-Pentanone

Answer 1

Answer: (D)

2-Pentanone

Answer 2

1. Formation of Ketone:

   • Starting Material: Propionitrile (CH₃CH₂CN).
   • Reaction with Ethyl Magnesium Iodide (EtMgI): The nucleophilic ethyl group adds to the electrophilic carbon of the –CN group, forming a magnesium imine complex.
   • Acidic Hydrolysis: This complex is hydrolyzed to yield a ketone. The structure of the product is CH₃CH₂COCH₂CH₃, which is 2-pentanone.

   Thus, the correct option for the product is (D) 2-Pentanone.