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Question: If osmotic pressure of 0.2 M aqueous glucose solution is 5 atm at 300 K. Calculate the concentration...

If osmotic pressure of 0.2 M aqueous glucose solution is 5 atm at 300 K. Calculate the concentration of glucose solution having osmotic pressure 2.5 atm at same temperature.

A

0.1 M

B

0.05 M

C

0.75 M

D

0.25 M

Answer

0.1 M

Explanation

Solution

Given the osmotic pressure formula:

π=MRT\pi = MRT

For glucose, the van’t Hoff factor i=1i = 1. Thus, osmotic pressure is directly proportional to the concentration:

π1π2=M1M2\frac{\pi_1}{\pi_2} = \frac{M_1}{M_2}

Substitute the given values:

5atm2.5atm=0.2MM2\frac{5\, \text{atm}}{2.5\, \text{atm}} = \frac{0.2\, \text{M}}{M_2}

This simplifies to:

2=0.2M2M2=0.22=0.1M2 = \frac{0.2}{M_2} \quad \Longrightarrow \quad M_2 = \frac{0.2}{2} = 0.1\, \text{M}