Question

$36\, g$ of glucose (molar mass $=180\,g/mol$ ) if present in $500\,g$ of water, the molality of the solution is

• A. 0.2
• B. 0.4
• C. 0.8
• D. 1

Answer 1

Answer: (B)

0.4

Answer 2

Molality, $m =\frac{\text { moles of solute } \times 1000}{\text { mass of solvent }(\text { in } g )}$
$=\frac{36 \times 1000}{180 \times 500}=0.4\, m$