Solveeit Logo
Login

Question

Question: \(34.05mL\)of phosphorus vapours weigh \(0.0625g\)at \(546^{0}C\)and \(0.1\)bar pressure. What is th...

34.05mL34.05mLof phosphorus vapours weigh 0.0625g0.0625gat 5460C546^{0}Cand 0.10.1bar pressure. What is the molar mass of phosphorus?

A

124.77gmol−1124.77gmol^{- 1}

B

1247.74gmol−11247.74gmol^{- 1}

C

12.47gmol−112.47gmol^{- 1}

D

30gmol−130gmol^{- 1}

Answer

1247.74gmol−11247.74gmol^{- 1}

Explanation

Solution

: M=mRTPV=0.0625×.0083×8190.1×(34.05/1000)M = \frac{mRT}{PV} = \frac{0.0625 \times .0083 \times 819}{0.1 \times (34.05/1000)}

=1247.74gmol−1= 1247.74gmol^{- 1}