Question

Out of 10 white, 9 black and 7 red balls, the number of ways in which selection of one or more balls can be made, is

Answer 1

879

Answer 2

The number of ways to select balls of a particular color is (number of balls + 1), as we can choose any number from zero up to the total available. For 10 white, 9 black, and 7 red balls, the total number of ways to select any number of balls (including zero) is $(10+1) \times (9+1) \times (7+1) = 11 \times 10 \times 8 = 880$. To find the number of ways to select one or more balls, we subtract the single case where no balls are selected. Result: $880 - 1 = 879$.